Astraight wire carrying a 3.30-a current is placed in a uniform magnetic field of magnitude 0.272 t directed perpendicular to the wire. (a) find the magnitude of the magnetic force on a section of the wire having a length of 12.7 cm. n (b) explain why you can't determine the direction of the magnetic force from the information given in the problem

F = 0.114 N

Explanation:

a) The magnetic force is given by the equations

    F = q v x B = I Lx B

the bold incate vector.  This equation can be used in the form of magnitude and find the direction separately with the rule of the right hand

    F = i L B sin θ

Where θ is the angle between the direction (L) and the magnetic field, if the two are perpendicular sin 90 = 1

Let's calculate

    F = 3.30 0.127 0.272

    F = 0.114 N

b) to know the direction of the magnetized field we must know the direction of B and L, but in the problem they tell us that they are perpendicular, but not the direction of each

the force on the thing and the distance the force moves the thing

490 n

f=125n a=2.5m/s2