Afair coin is tossed 3 times in a row. what is the probability that heads appears on only the last toss? a. `1/8` b. `3/8` c. `3/16` d. `3/4`

P(heads appears on only the last toss) =

Step-by-step explanation:

A fair coin is tossed 3 times in a row.

When a coin is tossed we get a tail or head T or H

The possible outcomes of 3 coins are

T T T , H H H , T H H, H T H, H H T, H T T , T H T, T T H

So total of 8 possible outcomes

heads appears on only the last toss , first and second toss should be tail

So its T T H. Only one possibility

Probability(any event)  = number of outcomes / total outcomes

P(heads appears on only the last toss) =

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42