Ab is dilated from the origin to create a'b' at a' (0,6) and b' (6, 9). what scale factor was ab dilated by?
1/2
2
3
4

The scale factor was 3

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

step 1

Find the distance AB

we have

A(0,2) and B(2,3) -----> see the figure

substitute in the formula

step 2

Find the distance A'B'

we have

A'(0,6) and B'(6,9) -----> given value

substitute in the formula

simplify

step 3

Find the scale factor

To find out the scale factor divide the length of the image A'B' by the length of the pre-image AB

so

therefore

The scale factor was 3

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

faster, im not sure why but i know it is faster