Mathematics

Mathematics, 14.07.2019 09:30, jenniferleeross53

Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i

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Mathematics, 11.07.2019 09:30, gilcarrillo146

1. which domain restrictions apply to the rational expression? x^2+5x+6 x^2-9 select each correct answer. x≠2 x≠1 x≠−3 x≠3 x≠−2 x≠−1 (4x)/(x-3)+(2)/(x^(2)-9)= (1)/(x+3) a. 19/3 b. 13/3 c. -5 d. -17/3 9. which statement best reflects the solution(s) of the equation? 1/x + 1/x-3 = x-2 / x-3 a. there is only one solution: x = 1. the solution x = 0 is an extraneous solution. b. there is only one solution: x = 1. the solution x = 3 is an extraneous solution. c. there is only one solution: x = 3. the solution x = 1 is an extraneous solution. d. there are two solutions: x = 1 and x = 3. 10. (√3x+1)−x+3=0 a. there is only one solution: x = 1. the solution x = 8 is an extraneous solution. b. there is only one solution: x = 8. the solution x = 1 is an extraneous solution. c. there is only one solution: x = 8. the solution x = 0 is an extraneous solution. d. there are two solutions: x = 1 and x = 8.

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Mathematics, 26.08.2019 23:30, madeleine1102

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Chemistry, 02.09.2019 18:20, aubreyfoster

Determine the molarity for each of the following solution solutions: (a)1.457 mol of kcl in 1.500 l of solution (b) 0.515 gram ofh2so4, in 1.00 l of solution (c) 20.54 g of al(no3)3 in 1575 ml of solution (d)2.76 kg ofcuso4.5h2o in 1.45 l of solution (e)0.005653 mol ofbr2 in 10.00 ml of solution (f) 0.000889 g of glycine,c2h5no2, in 1.05 ml of solution

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Chemistry, 02.09.2019 18:20, nyraimccall408

Determine the molarity for each of the following solution solutions: (a)0.444 mol of cocl2 in 0.654 l of solution (b) 98.0 gram of phosphoric acid, h3po4, in 100 l of solution (c) 0.2074 g of calcium hydroxide, ca(oh)2 in 40.00 ml of solution (d)10.5 kg of na2ao4.10h2o in 18.60 l of solution (e) 7.0 x 10-3 mol of l2 in 100.0 ml of solution (f) 1.8 x 104 mg of hcl in 0.075 of solution

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Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3...

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