Chemistry, 02.09.2019 18:20, nyraimccall408

Determine the molarity for each of the following solution solutions:
(a)0.444 mol of cocl2 in 0.654 l of solution
(b) 98.0 gram of phosphoric acid, h3po4, in 100 l of solution
(c) 0.2074 g of calcium hydroxide, ca(oh)2 in 40.00 ml of solution
(d)10.5 kg of na2ao4.10h2o in 18.60 l of solution
(e) 7.0 x 10-3 mol of l2 in 100.0 ml of solution
(f) 1.8 x 104 mg of hcl in 0.075 of solution

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answered: rebtav

A) 0,679 mol/L

B) 10 mol/L

C) 0.07000 mol/L

D) 3.97 mol/L

E) 0.070 mol/L

F) 6.6 mol/L

Explanation:

A) Molarity is the ration between the number of moles ins solution over the solution volume in liters.

Therefore the molarity of such solution is:

$M=\frac{n}{L}=\frac{0.444}{0.654} =0.679$

B) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol P=30.97 O=16.00

By adding the masses of the atoms in a molecule, we get its molecular weight.

H3P04 molecular mass is 3x1.00+30.97+4x16.00=97.97g/mol

The molar mass is used to calculate the number of moles of a molecule in a given sample.

$n=\frac{sample}{molar mass} = \frac{98.0}{97.97} =1.00$

Therefore the molarity of such solution is:

$M=\frac{n}{L}=\frac{1}{0.1} =10$

C) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol Ca=40.08 O=16.00

By adding the masses of the atoms in a molecule, we get its molecular weight.

Ca(OH)2 molecular mass is 2x1.00+40.08+2x16.00=74.08g/mol

The molar mass is used to calculate the number of moles of a molecule in a given sample.

$n=\frac{sample}{molar mass} = \frac{0.2074}{74.08} =0.002800$

Therefore the molarity of such solution is:

$M=\frac{n}{L}=\frac{0.002800}{0.0040} =0.07000$

D) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule. (assuming you meant Na2SO4)

Na=22.99 g/mol S=32.07 O=16.00

By adding the masses of the atoms in a molecule, we get its molecular weight.

Na2SO4 molecular mass is 2x22.99+32.07+4x16.00=142.05 g/mol

The molar mass is used to calculate the number of moles of a molecule in a given sample.

$n=\frac{sample}{molar mass} = \frac{10500}{142.05} =73.9$

Therefore the molarity of such solution is:

$M=\frac{n}{L}=\frac{73.9}{18.60} =3.97$

E) Molarity is the ration between the number of moles ins solution over the solution volume in liters.

Therefore the molarity of such solution is:

$M=\frac{n}{L}=\frac{0.0070}{0.1000} =0.070$

F) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.

H=1.00 g/mol Cl=35.45

By adding the masses of the atoms in a molecule, we get its molecular weight.

HCl molecular mass is 1.00+35.45=36.45g/mol

The molar mass is used to calculate the number of moles of a molecule in a given sample.

$n=\frac{sample}{molar mass} = \frac{18}{36.45} =0.49$

Therefore the molarity of such solution is:

$M=\frac{n}{L}=\frac{0.49}{0.075} =6.6$

answered: Guest

Ithink the answer is a or d.

answered: Guest

idk what the question is about

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Determine the molarity for each of the following solution solutions:
(a)0.444 mol of cocl2 i...