Def find_fib(n):
if n <= 2:
return 1
fib_x, fib_next = 1, 1
i = 3<...
World Languages, 16.07.2021 19:40, princessa15266
Def find_fib(n):
if n <= 2:
return 1
fib_x, fib_next = 1, 1
i = 3
while i <= n:
i += 1
fib_x, fib_next = fib_next, fib_x + fib_next
return fib_next
def list_fib(n):
fib_list = [1, 1]
if n <= 2:
return fib_list[:n]
fib_x, fib_next = 1, 1
i = 3
while i <= n:
i += 1
fib_x, fib_next = fib_next, fib_x + fib_next
fib_list. append(fib_next)
return fib_list
for x in range(1, 11):
print(find_fib(x))
print(list_fib(1))
print(list_fib(2))
print(list_fib(10))
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