Ahelicopter hovers 200 meters over the ground and releases a relief packet. how much time does it take for the food packet to reach the ground?

If it is hovering, you are being told that vi = 0 [The initial downward velocity is 0]

Givens

vi = 0
a =9.81 m/s
d = 200 m

Find

t

Formula

d = vi * t + 1/2a*t^2

Substitution and Work

200 = 0 + (1/2)* 9.81 * t^2
200 * 2 = a*t^2
400 = 9.81 * t^2
200 / 9.81 =  t^2
20.39 = t^2
t = sqrt (20.39)
t = 4.52 seconds.

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