From a cylinder of height of 24cm and base diameter 14cm, a cone having equal radius and height is hollowed out. Find the volume of the remaining solid of the cylinder.

2463 cm^3

Step-by-step explanation:

Given that a cylinder of height of 24cm and base diameter 14cm, a cone having equal radius and height is hollowed out. Find the volume of the remaining solid of the cylinder.

Let first calculate the volume of the cylinder

V = πr^2h

Where the radius = 7 cm

V = π × 7^2 × 24

V = 3694.5 cm^3

Let's calculate the volume of a cone

V = 1/3πr^2h

V = 1/3 × π × 7^2 × 24

V = 1/3 × 3694.5

V = 1231.5 cm^3

To Find the volume of the remaining solid of the cylinder, minus the volume of a cone from the volume of a cylinder

Remaining volume V = 3694.5 - 1231.5

V = 2462.99 cm^3

V = 2463 cm^3 approximately

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

answer

106 emergencies

step-by-step explanation: