Two large parallel conducting plates are 17 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. an electrostatic force of 2.9 ✕ 10-15 n acts on an electron placed anywhere between the two plate (neglect fringing). (a) find the electric field at the position of the electron.

The electrostatic force acting on a charge q is given by

where E is the electric field's intensity.

In our problem, the particle is an electron, so its charge is . We know the intensity of the force, so we can find the magnitude of the electric field at the point where the electron is located:

where the negative sign means that the force and the electric field have opposite direction, because the charge is negative.

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