Two large parallel conducting plates are 8.0 cm apart and carry equal but opposite charges on their facing surfaces. the magnitude of the surface charge density on either of the facing surfaces is 2.0 nc/m2. determine the magnitude of the electric potential difference between the plates.

18.1 V

Explanation:

The electric field between two parallel plates is given by the equation:

where

is the charge surface density

is the vacuum permittivity

For the plates in this problem,

So, the magnitude of the electric field is

Now we can find the potential difference between the plates, which is given by

where

d = 8.0 cm = 0.08 m is the separation between the plates

Substituting,

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find the sum of the two horizontal vectors and the sum of the two vertical vectors

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