A20000 kg rocket has a rocket motor that generates 3.0×105 n of thrust. part a what is the rocket's initial upward acceleration?

a=5.20 m/s²

Explanation:

Given Data

Thrust = T (N)=3.0×10⁵N

Mass=m=20000kg

To find

acceleration=a=?

Solution

Newton Second law states that

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

(resultant force F)=ma

a=(resultant force F)/m

where

(resultant force F) is (Thrust-weight)  

Weight = mg = 2.0^4 kg*9.8 N/kg = 1.96^5 N

a = (resultant force F) / mass

a = (T - mg)/m = (3.0^5 N - 1.96^5 N)/ 2.0^4 kg

a=5.20 m/s²

answer; ///(74) degrees is your answer..

the amount of current in the coil