Wave travelling along string is described by, y(x, t) = 0.005 sinl(80.0x - 3.0t) , Amplitude=?, wavelength = ?, Period = ? , Frequency=? Displacement y at x= 30 cm and time t=20 seconds.

In a wave equation,

y= A sin ( wt ± Kx)

GIVEN,

y(x, t) = 0.005 sinl(80.0x - 3.0t)

Amplitude= 0.005 m

wavelength = 2π/k

= 2π/80

= π/40

time period = 2π/w

=2π/3

Frequency= 3/2π

Displacement y(30,20) = 0.005 sin(80.30 -3.20)

=0.005 sin(2400-60)

=0.005 sin(2340)

=0.005 ×0 [sin2340 = sin(6.5 ×360) =0]

=0

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.