An oil drop carrying a charge of 3e falls under gravity with a constant velocity of 4.6x10 m/s between two metal plates 5mm apart. When a p. d of 4600V is applied to the plates, the drop rises steadily. Calculate; (1) Radius of oil drop (2) Velocity with which the oil drop rises [density of oll 900kgm viscosity of air 18x10 "Nim] assume the effect of air buoyancy is negligible​

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015