A -0.00125 C charge is placed 3.62 m from a +0.00333 C charge. What is the magnitude of the electric force between them?

The magnitude of the force between the charges is approximately -2,858.77 N

Explanation:

The given details are;

The magnitude of the given charges;

q₁ = -0.00125 C, q₂ = +0.00333 C

The distance between the charges, r = 3.62 m

The magnitude of the electric force between the charges, 'F', between two charged particles or objects is given as follows;

Where;

k = Constant = 9 × 10⁹ N·m²/C²

q₁ = The magnitude of charge on the first charged object = -0.00125 C

q₂ = The magnitude of charge on the second charged object = +0.00333 C

r = The distance between the charges = 3.62 m

Plugging in the values, gives;

The magnitude of the force between the charges, F ≈ -2,858.77 N

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