If 15g of iron reacts with 8.5g of oxygen, how many grams of iron oxide will be produced

23.5g of FeO

Explanation:

Hello,

The question above is asking us to find the mass of iron oxide produced from 15g of Fe and 8.5g of O. Well, to solve this question, we'll require the equation of reaction.

2Fe + O₂ → 2FeO

From the equation of reaction, 2 moles of Fe plus 1 mole of oxygen will produce 2 moles of FeO

Molar mass of Fe = 56g/mol

Molar mass of FeO = 72g/mol

Molar mass of O = 16 × 2 = 32g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of Fe = 2 × 56 = 112g

Mass of O = 32g

Mass of FeO = 2 × 72 = 144g

From the equation of reaction, (112 + 32)g (Fe + O2) reacts to produce 144g of FeO

114g of reacts produce 114g of FeO

15g of Fe + 8.5g of O2 = ?

(15 + 8.5)g (Fe + O2) = x

X = (23.5 × 114) / 114

x = 23.5g

Therefore, 15g of Fe and 8.5g of O2 will react to produce 23.5g of FeO

6.4 cm (max) - 25 cm (min)