An archer shoots an arrow 75 m distant target; the bull's-eye of the target is at the same height as the release height of the arrow. If d = 75 m and v = 37 m/s. At what angle must the arrow be released to hit the bull's-eye if its initial speed is 37 m/s?

Explanation:

R = Horizontal range of projectile = 75 m

v = Velocity of projectile = 37 m/s

g = Acceleration due to gravity =

Horizontal range is given by

The angle at which the arrow is to be released is .

answer: b.

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.