Use Coulomb's law to determine the magnitude of the electric field at points A and B in (Figure 1) due to the two positive charges (Q = 5.9 μC ) shown. Suppose that a = 5.3 cm Determine the magnitude of the electric field at point B.
Determine the angle between the direction of the electric field at point B and the positive x-direction.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over

the components of a vector are the parts of the vectors that are to each other.

b perpendicular