The first 10 m of a 100 m dash are covered in 2 s by a sprinter who from rest and accelerates constantly. The remaining 90 m is run wit
same velocity the sprinter had after 2 s. In this context, answer the follo
questions.
Calculate the sprinter's constant acceleration during the first 2 s.
What is the sprinter's velocity after 2 s?
- Calculate the total time required to run the full 100 m.
1 Draw the displacement-time graph for the sprinter.
Classify the following situations as examples of balanced' and 'unbala
orces.
Two forces of 20 N acting towards left.
accelerating nlane

Calculate the sprinter's constant acceleration during the first 2 s:

Given that,

s = 10m

u = 0 m/s

t = 2s

What is the sprinter's velocity after 2 s?

v = u + at

given,

t = 2s

a = 5 m/s²

u = 0 m/s

v = 0 + (5 × 2)

v = 10 m/s

- Calculate the total time required to run the full 100 m.

first 10m is completed by 2 seconds.

and it is stated that The remaining 90 m is run wit

same velocity the sprinter had after 2 s.

For the rest 90m,

s = vt

v= 10 m/s

t = ?

s = 90

t = 90 ÷ 10

t = 9s

total time : (2+9) = 11 seconds

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answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.