The burner on an electric stove has a power output of 2.0 kW. A 650 g stainless steel tea kettle is filled with 20∘C water and placed on the already hot burner. If it takes 2.70 min for the water to reach a boil, what volume of water, in cm^3, was in the kettle?

The  value is    

Explanation:

From the question we are told that

  The  power output is  

   The  mass of the steel is  

    The  temperature of the water is

     The  time take is  

Generally the quantity of heat energy given out by the  electric stove is mathematically represented as

=>    

=>    

This energy can also be mathematically represented as

Here   is the specific heat of stainless steel with value  

 tex]c_s[/tex] is the specific heat of water  with value  

  m_w is the mass of water which is mathematically represented as

=>  

So

converting to

this means that the temperature of both substances will be equal

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.