Physics, 08.04.2020 01:30, Valduarte07

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find themotion somewhat unpleasant. To take your mind off your stomach, youwonder about the motion of the ride. You estimate the radius of thebig wheel to be 15 , and you use your watch tofind that each loop around takes 25 .

a. What is your speed?
b. What is the magnitude of your acceleration?
c. What is the ratio of your weight at the top of the ride to yourweight while standing on the ground?
d. What is the ratio of your weight at the bottom of the ride toyour weight while standing on the ground?

Answers: 3

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Answers

answered: lindsaypre0644

a. 0.0628 m

b. 0.000263 m/s2

c.99.997%

d.100.003%

Explanation:

Suppose the radius is 15 m and each loop takes 25 minutes (25*60 = 1500 seconds) to complete. The circumference of the Ferris wheel would be

C = 2πR = 2π*15 = 94.25 m

The your speed is the length of each loop per unit of time to complete each loop

v = C/t = 94.25 / 1500 = 0.0628 m/s

b. Since the circular motion is constant, the only acceleration from the motion is the centripetal acceleration, which can be calculated as the following:

a_c = v^2/r = 0.0628^2/15 = 0.000263 m/s^2

c. Let g = 9.8 m/s^2. At top of the ride, the centripetal acceleration would be pushing you up, while gravity pushes you down, so the weight you experience (compare to standing on ground would be):

$\frac{g-a_c}{g} = \frac{9.8 - 0.000263}{9.8} = 0.99997 = 99.997 \%$

d. At the bottom of the ride, both centripetal acceleration and gravity would be pushing you downward, making you feel like

$\frac{g+a_c}{g} = \frac{9.8 + 0.000263}{9.8} = 1.00003 = 100.003 \%$

answered: aletadaboss

a) The speed is 3.77 m/s

b) The acceleration is 0.948 m/s²

c) The ratio of your weight at the top to your weight standing on the ground is 0.903

d) The ratio of your weight at the bottom of the ride to your weight while standing on the ground is 1.097

Explanation:

a) The speed of the wheel is equal to:

v=rw

Where

r = radius of the circle = 15 m

w = angular velocity

$w=\frac{2\pi }{T}$

$v=\frac{2\pi r}{T} =\frac{2\pi *15}{25} =3.77m/s$

b) The acceleration is:

$a=\frac{v^{2} }{r} =\frac{3.77^{2} }{15} =0.948m/s^{2}$

c) Applying the Newton´s second law:

$W_{true} -N=ma\\W_{true}-N=\frac{mv^{2} }{r} \\N=W_{app} =W_{true}-\frac{mv^{2} }{r}$

Dividing the expression by Wtrue:

$\frac{W_{app}}{W_{true} } =1-\frac{mv^{2} }{rW_{true}} \\\frac{W_{app}}{W_{true} }=1-\frac{v^{2} }{rg} =1-\frac{3.77^{2} }{15*9.8} =0.903$

d) Applying the Newton´s second law:

$N-W_{true}=ma\\N-W_{true}=\frac{mv^{2} }{r} \\N=W_{app} =W_{true}+\frac{mv^{2} }{r}$

Dividing the expression by Wtrue:

$\frac{W_{app}}{W_{true} } =1+\frac{mv^{2} }{rW_{true}} \\\frac{W_{app}}{W_{true} }=1+\frac{v^{2} }{rg} =1+\frac{3.77^{2} }{15*9.8} =1.097$

answered: Guest

“when two plates carrying continents collide, the continental crust buckles and rocks pile up, creating towering mountain ranges. when an ocean plate collides with another ocean plate or with a plate carrying continents, one plate will bend and slide under the other. this process is called subduction. “ i found this on google i hope it

answered: Guest

answer and explanation;

composition refers to both the types of minerals within a rock and the overall chemical makeup of the rock while texture refers to the size and arrangement of the minerals or grains that make up a rock. both composition and texture can be used to classify rocks, such as igneous rocks. texture describes how the rock became solid or crystallized from liquid, melted rock. composition of a rock describes the minerals that make up a particular rock.

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While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples an...