A equação horaria de um movel e dada por S=10-2T. Encontre a posição inicial, velocidade e o instante que ele passa pela origem(s=0)

the answer is 3.1 his answer is wrong mines is right

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west