A potential difference V = 100 V is applied across a capacitor arrangement with capacitances C1 = 10.0 mF, C2 = 5.00 mF, and C3 = 4.00 mF. What are:

a. charge q3.
b. potential difference V3.
c. stored energy U3 for capacitor 3.
d. q1
e. V1
f. U1 for capacitor 1
g. q2
h. V2.
i. U2 for capacitor 2?

Given Information:

Potential difference = V = 100 V

Capacitance C₁ = 10 mF

Capacitance C₂ = 5 mF

Capacitance C₃ = 4 mF

Required Information:

a. Charge q₃

b. Potential difference V₃

c. Stored energy U₃

d. Charge q ₁

e. Potential difference V₁

f. Stored energy U₁

g. Charge q  ₂

h. Potential difference V₂  

i. Stored energy U₂

a. Charge q₃ = 0.4 C

b. Potential difference V₃  = 100 V

c. Stored energy  U₃  = 20 J

d. Charge q ₁  = 0.33 C

e. Potential difference  V₁  = 33 V

f. Stored energy U₁  = 5.445 J

g. Charge q  ₂ = 0.33 C

h. Potential difference V₂  = 66 V

i. Stored energy U₂ = 10.89 J

Explanation:

Please refer to the circuit attached in the diagram

a. Charge q₃

As we know charge in a capacitor is given by

q₃ = C₃V₃

q₃ = 4x10⁻³*100

q₃ = 0.4 C

b. Potential difference V₃

The potential difference V₃  is same as V

V₃  = 100 V

c. Stored energy U₃

Energy stored in a capacitor is given by  

U₃  = ½C₃V₃²

U₃  = ½*4x10⁻³*100²

U₃  = 20 J

d. Charge q ₁

Since capacitor C₁ and C₂ are in series their equivalent capacitance is

Ceq = C₁*C₂/C₁ + C₂

Ceq = 10x10⁻³*5x10⁻³/10x10⁻³ + 5x10⁻³

Ceq = 3.33x10⁻³ F

q ₁ = Ceq*V

q ₁ = 3.33x10⁻³*100

q ₁ = 0.33 C

e. Potential difference V₁

V₁  = q ₁/C₁

V₁  = 0.33/10x10⁻³

V₁  = 33 V

f. Stored energy U₁

U₁  = ½C₁V₁²

U₁  = ½*10x10⁻³*(33)²

U₁  = 5.445 J

g. Charge q  ₂

q₂ = Ceq*V

q₂ = 3.33x10⁻³*100

q₂ = 0.33 C

h. Potential difference V₂  

V₂  = q ₂/C₂

V₂  = 0.33/5x10⁻³

V₂  = 66 V

i. Stored energy U₂

U₂ = ½C₂V₂²

U₂ = ½*5x10⁻³*(66)²

U₂ = 10.89 J

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles