A slab of glass with an index of refraction of 1.65 is submerged in a liquid with an index of refraction of 1.22. Light in the liquid is incident on the glass.
(a) Find the angle of refraction for the angle of incidence of 60°.
°

(b) Find the angle of refraction for the angle of incidence of 45°.
°

(c) Find the angle of refraction for the angle of incidence of 30°.

Explanation:

Given that,

Refractive index of glass, n₁ = 1.65

Refractive index of liquid, n₂ = 1.22

(a) We need to find the angle of refraction for the angle of incidence of 60°. It can be calculated using Snells law as :

r is the angle of refraction

(b)

r is the angle of refraction

Here, i = 45 degrees

(c)  

r is the angle of refraction

Here, i = 30 degrees

Hence, this is the required solution.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is