Apiano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 n . a wave with frequency 105 hz and amplitude 1.80 mm travels along the wire.

(a) calculate the average power carried by the wave.
(b) what happens to the average power if the wave amplitude is halved?

The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

Here,

= Linear mass density of the string

 Angular frequency of the wave on the string

A = Amplitude of the wave

v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

Here T is the Period

For the linear mass density we have that

And the angular frequency can be written as

Replacing this terms and the first equation we have that

PART A ) Replacing our values here we have that

PART B) The new amplitude A' that is half ot the wavelength of the wave is

Replacing at the equation of power we have that

c. newton's third law of motion

your answer is, orbit around the nucleus