Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) find the net gravitational force exerted by these objects on a 69.0 kg object placed midway between them.

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.