Aparticle moves through an xyz coordinate system while a force acts on it. when the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is f with arrow = fxi hat + (7.00 n)j − (5.80 n)k and the corresponding torque about the origin is vector tau = (3.40 n · m)i hat + (2.80 n · m)j + (0.800 n · m)k. determine fx.

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

once a carousel is in motion, the constant movement of the carousel horse around the center of the circle can best be described asacceleration or change in velocity.