This figure shows how to create a six-pointed star from twelve equilateral triangle tiles: [asy]
size(7cm);
pair cis(real magni, real argu) { return (magni*cos(argu*pi/180),magni*sin(a rgu*pi/180)); }

for(int i=90;i<450;i+=60) {
pair c=cis(1.2,i);
path p=c-cis(1,i)--c-cis(1,i+120)--c-cis (1,i-120)--cycle;
fill(p, orange+white);
draw(p);
pair c=cis(2.4,i);
path p=c+cis(1,i)--c+cis(1,i+120)--c+cis (1,i-120)--cycle;
fill(p, orange+white);
draw(p);
};

label("$\longrightarrow$",(4,0)); pair x=(8,0);
real s=sqrt(3);
path p=x+cis(s,0)--x+cis(3,30)--x+cis(s, 60)--x+cis(3,90)--x+cis(s,120)--x+c is(3,150)--x+cis(s,180)--x+cis(3,21 0)--x+cis(s,240)--x+cis(3,270)--x+c is(s,300)--x+cis(3,330)--cycle;
fill(p, orange+white);
draw(p);
[/asy]
If each of the original tiles has a perimeter of $10$ cm, what is the perimeter of the final star in cm?

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true