Agymnast is in a tucked position to complete her somersaults. while tucked her moment of inertia about an axis through the center of her body is 16.0 kg-m² and she rotates at 2.5 rev/s. when she kicks out of her tuck into a straight position, her moment of inertia becomes 19.5 kg-m². what is her rate of rotation after she straightens out?

Explanation:

Given that:

Now using the law of conservation of angular momentum:

angular momentum of tucked body=angular momentum of straight body

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.