You want the current amplitude through a inductor with an inductance of 4.30 mh (part of the circuitry for a radio receiver) to be 3.00 ma when a sinusoidal voltage with an amplitude of 12.0 v is applied across the inductor. a) what frequency is required? f = .

Explanation:

For the circuit of the radio knowing the voltage in a inductor is VL and the relation of element is:

Where , , and

Knowing that the frequency influence in the performance of the inductor so:

Solve to f'

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96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.