Cliff divers at acapulco jump into the sea macias (fjm793) – homework 3, 2d motion 19-20 – dowd – (woffordwphy11920 2) 4 from a cliff 36.2 m high. at the level of the sea, a rock sticks out a horizontal distance of 11.98 m. the acceleration of gravity is 9.8 m/s 2 . with what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss the rock? answer in units of m/s.

v = 7.67 m/s

Explanation:

Given data:

horizontal distance 11.98 m

Acceleration due to gravity 9.8 m/s^2

Assuming initial velocity is zero

we know that

solving for t

we have

substituing all value for time t

t = 1.56 s

we know that speed is given as

v = 7.67 m/s

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.