How do you define two angles which will result in a range of zero for a projectile launched at an angle to the horizontal

Oh what a sneaky problem ! 

The "range" of a projectile is how far out away from the gun it goes
before it falls to the ground.

The question is asking you:  "What angle should you aim the gun
above the horizon so that the bullet doesn't go any distance away
from the gun, and it hits the ground exactly where the gun is "
And there are two different answers.  Really sneaky !

Can you think of how you could fire the gun so that the bullet would
hit the ground right under the gun ?  How about pointing the gun at
the ground ... aiming 90 degrees below the horizon ?  That would
certainly do it.                Is there another way to do it  ?

How about aiming the gun straight up in the air ... 90 degrees above
the horizon ?  Then it goes up, up, up, runs out of steam, stops rising,
starts falling, comes down, down, down, and hits the ground right where
the gun was.

As long as there's no air and no wind, the two angles are +90 degrees
and -90 degrees above the horizon. 

' +90 above ' means straight up.  ' -90 above ' means straight down.

Since the pully is a simple machine so the mechanical advantage is a 1