(part 1 of 3)
a boat moves through the water with two forces acting on it. one is a 2.90×103 n forward push by the motor, and the other is a 1.69×103 n resistive force due to the water.
what is the acceleration of the 1177.5 kg boat?
1.0276
(part 2 of 3)
if it starts from rest, how far will it move in 17.7 s?
160.969
(part 3 of 3)
what will be its speed at the end of this time?
unknown

i need answer for part 3

1)

We can solve this part by using Newton's second law:

(1)

where

F is the net force

m is the mass

a is the acceleration

There are two forces acting on the boat:

forward

backward

So the net force is

We know that the mass of the boat is

m = 1177.5 kg

So we can now use eq.(1) to find the acceleration:

2) 161.0 m

We can solve this part by using the following suvat equation:

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

Here we have

u = 0 (the boat starts from rest)

Substituting t = 17.7 s, we find the distance covered:

3) 18.2 m/s

The speed of the boat can be found with the following suvat equation

where

v is the final velocity

u is the initial velocity

t is the time

a is the acceleration

In this case we have

u = 0 (the boat starts from rest)

And substituting t = 17.7 s, we find the final velocity:

And the speed is just the magnitude of the velocity, so 18.2 m/s.

im sorry i dont know

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