Atennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 28.0 m/s and returns the shot with the ball traveling horizontally at 41.0 m/s in the opposite direction. (assume the initial direction of the ball is in the −x direction.)

Impulse, J = 4.14 kg-m/s          

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = -28 m/s (it is assumed that the initial direction of the ball is in the -x direction)

Final speed of the ball, v = 41 m/s

It can be assumed to find the impulse delivered to the ball by the racket. The impulse delivered is equal to the change in momentum of the object. Mathematically, it is given by :

J = 4.14 kg-m/s

So, the impulse delivered by the ball to the racket is 4.14 kg-m/s. Hence, this is the required solution.

true

explanation:

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6