Aphysics student stands on the rim of the canyon and drops a rock. the student measures the time for it to reach the bottom to be 3.2 seconds. how deep is the canyon?

Canyon is 50.176 meter deep.

Explanation:

The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.

Given data:

Time = t = 3.2 s

Initial velocity = = 0 m/s

Gravitational acceleration = g = 9.8 m/s²

Height = h = ?

According to second equation of motion

As initial velocity is zero, So the first term of right hand side of above equation equal to zero

h = (0.5)(9.8)(3.2)²

h = 50.176 m

This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.

c) up is the direction the magnetic force is acting on the charge.