Consider a thin spherical shell of radius 14.0 cm with a total charge of +31.0 µc distributed uniformly on its surface. (take radially outward as the positive direction.) (a) find the electric field 10.0 cm from the center of the charge distribution. 10167638.48 incorrect: your answer is incorrect. your response differs significantly from the correct answer. rework your solution from the beginning and check each step carefully. n/c (b) find the electric field 23.0 cm from the center of the charge distribution.

electric field = 0

electric field  = 8.95 × MN/C

Explanation:

given data

radius = 14.0 cm

total charge = +31.0 µC = 31 × C

to find out

electric field 10.0 cm from the center of the charge and Find the electric field 23.0 cm from the center of the charge distribution

solution

we know that here for a spherical shell

electric field inside = 0

and electric field outside =

and here we can say that 10 cm in inside

so electric filed E = 0

and

when radius is 23 cm

so

electric field =

electric field =

electric field  = 8.95 × MN/C

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​