What is the width of this rectangle?
WWJD

3rd or 2nd

Step-by-step explanation: To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width. In other words, the area of a rectangle is the product of its length and width. That is, A = l x w where l is the length and w is the width of the rectangle. For example, the area of a rectangle of length 35 m and width 25 m is 35 times 25 or 875 square meters. A rectangle is composed of two sides namely, length (L) and width (W). The length of a rectangle is the longest side whereas the width is the shortest side. The width of a rectangle is sometimes referred to as the breadth (b).

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.