Dont have to answer all but with whatever you can will , you. scenario
a rock is thrown horizontally with speed v from the top of a cliff of height h,
as shown in the diagram to the right.
using representations
part a: on the diagram, choose a location for a horizontal and vertical origin. label
your choice with x = 0 and y = 0 on the diagram. choose a horizontal and
vertical positive direction and label those directions on the diagram using
arrows.
quantitative analysis
part b: identify an equation that can be used to solve for the time it takes the rock to hit the ground. write
the equation below. (if you're having trouble finding the right equation, refer to your notes, your
textbook, or the ap physics 1 equation sheet.)
part c: rearrange the equation you wrote above in part b to solve for the time it will take the rock to hit the
water. your final equation should only contain given variables and physical constants. (h, v, and
physical constants as necessary).
part d: identify an equation that can be used to solve for the horizontal distance between the bottom of the
cliff and the place where the rock lands. write the equation below.
parte: rearrange the equation you wrote above in part d to solve for the horizontal distance d between
the bottom of the cliff and the place where the rock lands. answer in terms of h, v, and physical
constants as necessary.
d=

a.H = gt2/2.

b  t = (2H/g)1/2

c.D = vt,

D = v (2H/g)^1/2

Explanation:

Dont have to answer all but with whatever you can will help, thank you. Scenario

A rock is thrown horizontally with speed v from the top of a cliff of height H,

as shown in the diagram to the right.

Using Representations

PART A: On the diagram, choose a location for a horizontal and vertical origin. Label

your choice with x = 0 and y = 0 on the diagram. Choose a horizontal and

vertical positive direction and label those directions on the diagram using

arrows.

Quantitative Analysis

PART B: Identify an equation that can be used to solve for the time it takes the rock to hit the ground. Write

the equation below. (If you're having trouble finding the right equati

the bottom of the cliff, the ground, and the water are at the same level (this was not stated clearly in the problem). An assumption although

(a)

If there is no air resistance,

from newton's equation of motion, we can say that

s=ut+1/2gt^2

s=H, the height of the rock to the ground level

a=g

u=0, the initial velocity for vertical motion

t is the time of flight it took the rock from the origin ,then through the projectile path down to the ground

H = gt^2/2.

where

t = time

g = acceleration of gravity

(b)  from equation a, we can make t the subject of the equation

t = (2H/g)1/2

(c)

D = vt,  

t=d/v

with t computed in part (b).

(d)

D = v (2H/g)1/2

the answer is a 3.8cm

explanation: