This time particle a starts from rest and accelerates to the right at 65.5 cm/s
2
. particle
b starts 349 cm down the track and moves at
a constant velocity of 44 cm/s to the left.
when will they meet?
answer in units of s.

t = 4 s

Explanation:

As we know that the particle A starts from Rest with constant acceleration

So the distance moved by the particle in given time "t"

Now we know that B moves with constant speed so in the same time B will move to another distance

now we know that B is already 349 cm down the track

so if A and B will meet after time "t"

then in that case

on solving above kinematics equation we have

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat