A bug spray's effectiveness decreases over time. After h weeks, it retains only half of its effectiveness, and this trend continues. A function that represents this is Q(t) = 30•6^5-1

A scientist testing the bug spray tried to put the given equation into the form (t) = Q0(1/2)^t/h
where t is measured in years, but she got stuck. Her work is shown here.

Step 1 Q(t) = 30•6^5-t
Step 2 Q(t) = 30•6^5 •6^-t
Step 3 Q(t) = 233,280 - (1/6)^t
Step 4 Q(1) = 233,280•(1/6)^h•(t/h)
Step 5 Q(t) = 233,280 •((1/6)^h)•(t/h)
A: If (1/6)^h = 1/2, what is h to the nearest hundredth?

757764

step-by-step explanation:

de77737dd

whatvare the choices

step-by-step explanation:

191 students play sports and ninety-seven 10th graders were surveyed.

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺