Consider a wod raft with length = 5.0m, width 3.0 m and height = 1.0m, with density =600kg/m^3. there is an object of a mass of 500 kg standing on the raft. how deep will it sink into the water of density 1000 kg/m^3?

0.63333m

Explanation:

If the wood raft partially sinks, it means the water exerts a force upwards, equal to the weight of the displaced water by the part sank that is in magnitude equal to the weight of the raft and the objects on it but the opposite direction.  There fore, we need to calculate the mass of the raft and add it to the object mass for the total.

Where is the volume of the raft and is the density.

The total mass is 9500Kg (The raft plus the object), and this is equal to the mass of the water displaced. Now find the volume of water that has this mass:

With this volume you can calculate at what height of the raft the water will be. The base of the raft will be the same, just calculate the new height.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle