Solve in systems by substitution y=2x+1 and 2x-y=3

No Solution

Step-by-step explanation:

y=2x+1 and 2x-y=3

Substitute y=2x+1 into 2x-y=3

So you will have: 2x-2x+1=3

Then,

2x-2x=0

0+1=3

1=3

1 doesn't equal 3 so there is no solution.

No solution.

Step-by-step explanation:

Notice that the second equation can be rearranged to be y = 2x - 3. 2x + 1 cannot equal 2x - 3 so there is no solution to this system.

so, converting firstly the mixed fractions to improper fractions and then "adding".