2. a rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μc. determine the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod.

Explanation:

It is given that,

Length of rod, l = 14 cm = 0.14 m

Total charge,

We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m

Electric field at the axis of rod is given by :

Where

is the linear charge density,

So,

E = −7849988.22 N/C

or

Negative sign shows the direction of electric field is inward in all direction. Hence, this is the required solution.

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