HELP HELP Tommy rides in a motorboat against a river current for 25 km. Then he returns to his starting point by floating down river on a raft. Tommy travels 10 hours less on the motorboat than on the raft. Find the speed of the river current if the speed of the motorboat in still water is 12 km/h.

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2

Step-by-step explanation:

2 km/h

Step-by-step explanation:

You can make a rate-time-distance chart to help you figure it out.

          |    R    |    D    |    T    

MB     |  12-x  |   25   | 25/(12-x)

Raft    |    x    |    25   | 25/x

This means that the speed of the current in this case is x. The speed of the raft is also x because it is traveling with the current. The speed of the motorboat would be 12-x because you have to factor in the current. The time for both of them is the distance divided by the speed.

You also have another relationship that you know about. You know that the time it takes to travel by raft is 10 more than the time it takes to travel by motorboat. This means that to make 25/(12-x) and 25/x equal you would need to add ten to the 25/(12-x)

This gives you the equation:

25/(12-x)  +  10  =   25/x

From there you can start solving

(25+120-10x)/(12-x)=25/x

Then you cross multiply and get:

300-25x=145x-10x^2

Then you put everything to one side and get:

10x^2-170x+300=0

Then you factor out the 10 and get:

10(x^2-17x+30)=0

Then you can factor x^2-17x+30 and get (x-2)(x-15)

From there you can apply the zero product property and say that

x-2=0

x=2

And that

x-15=0

x=15

Now you have two solutions but the answer can't be 15 because if you do 12-15 to find the speed of the motorboat you would get a negative number and speed cannot be negative. Therefore the only possible answer is 2.

Hope this helps and let me know if something doesn't make sense in my solution!

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant