An 1450 w toaster and an 923 w microwave oven are connected in parallel to the same 25.0 a, 120 v circuit. hint (a) find the toaster's resistance r (in ohms). (b) if the microwave fails and is replaced, what maximum power rating (in w) can be used without tripping the 25.0 a circuit breaker?

The maximum power rating of a device that can be used in place of the

microwave depends on the power ratings of the circuit and the toaster.

Power rating of the toaster = 1,450 W

Power rating of the microwave = 923 W

Current in the circuit  = 25.0 A

Voltage of the circuit, V = 120 V

(a) The resistance of the toaster is given as follows;

Power, P = I²·R = V·I

Therefore;

Which gives;

For a circuit arranged in parallel, V is constant, therefore;

(b) The power rating of the circuit, = 25.0 A × 120 V = 3,000 W

Power rating of the microwave = 1,450 W

The maximum power rating (in W) of a device that can be used without tripping the 25.0 A circuit breaker is therefore;

3,000 W - 1,450 W = 1,550 W

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Part a)

R = 9.93 ohm

Part b)

P = 2375 W

Explanation:

Part a)

Resistance of the toaster is given as

here we know that

P = power of device

V = voltage across the device

now we have

Part b)

when microwave fails and replaced

then here the current flowing in toaster is given as

similarly current in the microwave is given as

now total current in it is

So power rating is given as

the rearrangement of particles in a physical change. hope this

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