In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 150 cm. what is the phase difference (in degrees) between the waves from the two slits arriving at a point p when the angular distance of p is 10° relative to the central peak, and the wavelength is 500 nm? (convert your result so the angle is between 0 and 360°.)

The answer is: 6.3mi got it right

Accelerating forwards; fa > ff            fn                           |ff< · > fa                      |                     fgfn = fg. so ∑f is just equal to sum of fa and ff (fn and fg cancel)find the distance the pickle travels. v₀ = 0 m/sd = 6.0 mt = 4.0 suse kinematic equationd = v₀t + at²/2d = 0t + at²/2d = at²/2a = 2d/t²a = 2(6.0 m)/(4.0 s)² a = 0.75 m/s² forwards∑f = fa + ffwe are given that ff = 3.8 n backwardsfa = ∑f - fffa = ma - ff fa = (25.0 kg)(0.75 m/s²) - (-3.8n)fa = 22.55 n forwardssow = fa · dw = (22.55 n)(6.0 m)w = 135 jw = 140 jthe work done to move the object is 140 j.

Answer/// the energy that does not do useful work is converted into thermal energy