Use any test to determine whether the series is absolutely convergent, conditionally convergent, or divergent. ∞ (−1)n arctan(n) n5 n = 1 absolutely convergent conditionally convergent divergent

Determine whether  the  geometric series.  ∞. ∑  n=1  en. 3n−1  is  convergent  or  divergent. if it isconvergent, find its sum. answer: i can re-write the terms as en. 3n−1  (  n n  +  1. ) = lim  n→∞  sn = limn→∞. (−ln(n  +  1)) =  −∞, so the given series diverges. 48. find the values of x for which the series.  ∞. ∑n=1. (x  − 4)n converges.