What is the final volume in milliliters when 0.781 L of a 43.4 % (m/v) solution is diluted to 20.8 % (m/v)?

1629.33 mL

Explanation:

To do this, we need to use the correct expression. WE are talking about %m/V, and the expression for this is:

%m/V = m solute / V solution * 100

We have the volume of solution, and the initial concentration. With these data we can calculate the mass of solute, which will remain constant when the solution is being dilluted. From above we can solve for mass of solute:

m solute = %m/V * V solution / 100

Replacing we have:

m = 43.4 * 0.781 / 100 = 0.3389 g

With this value, we solve for V of solution now, but with the concentration of 20.8%:

V solution = m solute / %m/V * 100

V solution = 0.3389 / 20.8 * 100

V Solution = 1.62933 L

This will be the final volume in liters. In mililiters is:

V = 1629.33 mL

Explanation:

Hello,

In this case, by using the dilution equation wherein we assume that the mass of the solute remains unchanged:

We must compute the the final final given the initial volume and the both the initial and final concentrations in %m/v as shown below:

Best regards.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."