In the game of roulette, a player can place a $55 bet on the number 3434 and have a startfraction 1 over 38 endfraction 1 38 probability of winning. if the metal ball lands on 3434, the player gets to keep the $55 paid to play the game and the player is awarded an additional $175175. otherwise, the player is awarded nothing and the casino takes the player's $55. what is the expected value of the game to the player

the correct question is
In the game of roulette, a player can place a $5 bet on the number 34 and have a 1/38 probability of winning. if the metal ball lands on 34, the player gets to keep the $5 paid to play the game and the player is awarded an additional $175. otherwise, the player is awarded nothing and the casino takes the player's $5. what is the expected value of the game to the player

we know that
P(winning) = 1/38 
P(losing) = 1-1/38 = 37/38 
Expected value = 175*1/38 - 5*37/38 
175/38 - 185/38 = - 10/38 =-$0.2632

The player's expected value is -$0.2632 ( is losing)

Iagree that is the answer to the question