With where to !
at an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point. assume at x = 0 the buoy is at normal ocean depth.

use the sine tool to graph the function. the first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

Answer with explanation:

It is given that:

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth.

Sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point.

Assume at x = 0 the buoy is at normal ocean depth.

this means that when x=0 the value on the y-axis is -8.

Also, the buoy bobs up 5 meters up so the maximum height reached by him is -3.

( Since -8+5=-3)

So, the sine function that will represent this situation  is:

Now, the graph of this situation is attached to the answer and the mid-line and the first and the second points on it are labelled.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐