Arectangular school banner has a length of 48 inches and a width of 30 inches. a sign is made that is similar to the school banner and has a length of 15 inches. what is the ratio of the area of the school banner to the area of the sign?

The ratio of length to width is:

ratio = 48 inches / 30 inches = 1.6

This ratio must be similar to that of the other school banner, therefore the width of that is:

width = 15 / 1.6 = 9.375 inches

The areas are:

A1 = 48 inches * 30 inches = 1440 square inches

A2 = 15 inches * 9.375 inches = 140.625 square inches

So the ratio of the area is:

A1 / A2 = 1440 / 140.625

A1 / A2 = 10.24

i think this could be a possible answer (1 / 84) -1

good luck! : d

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.